Find the greatest number 23a68b, which is divisible by 3 but NOT divisible by 9.
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 239685
We have given a number that is 23a68b.
The number is divisible by 3 if the sum of the digits of the number is divisible by 3.
The number is divisible by 3 if the sum of the digits of the number is divisible by 9.
So,
2 + 3 + a + 6 + 8 + b =19 + a + b