Find the greatest 3-digit number which, when divided by 3,4,5 and 8, leaves remainder 2 in each case.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 962
The number will be of the form LCM(3,4,5,8)k + 2
LCM(3,4,5,8) = 120
The number will be of the form 120k + 2
The greatest 3 digit number is 120 × 8 + 2 = 960 + 2 = 962