Find the area of the quadrilateral ABCD, the coordinates of whose vertices are A(6, -3), B(-4, -2), C(3, 1) and D(5, 0)?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 21 unit2 .
Area = 1/2∣x1y2 + x2y3 + x3y4 + x4y1 − (y1x2 + y2x3 + y3x4 + y4x1)∣
Area = 1/2∣(6⋅(−2) + (−4)⋅1 + 3⋅0 + 5⋅(−3)) - (−3⋅(−4) + (−2)⋅3 + 1⋅5 + 0⋅6)∣
Area = 1/2∣(−12 − 4 + 0 − 15) - (12 - 6 + 5 + 0)∣
Area = 1/2∣-31 - 11∣
Area = 1/2 × 42 = 21 unit2