Find the area of a rhombus if the perimeter of the rhombus is 52 cm, and one of its diagonals is 10 cm long.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 120 cm2.
Given that
The perimeter of the rhombus is 52 cm
One of its diagonals is 10 cm long
Area of rhombus = ½ × d1 × d2, where d1 and d2 are the lengths of the diagonals
Perimeter of rhombus = 2√(d12 + d22)
According to the question
⇒ 2√(d12 + d22) = 52
⇒ (d12 + d22) = 262 = 676
⇒ d12 + 100 = 676
⇒ d12 = 676 - 100 = 576 cm
⇒ d1 = 24 cm
Hence, Area of the rhombus = 24 × 10/2 = 120 cm2