SSC MTS 2026 PYQ — Question 9

SSC MTS - 10 Feb 2026 - Shift 2 • Quantitative Aptitude • Q9

Find the approximate value of:
169.89×101.9616.93×33.98+198.11×120.8732.89×35.97=?\frac{169.89 \times 101.96}{16.93 \times 33.98} + \frac{198.11 \times 120.87}{32.89 \times \sqrt{35.97}} = ?

Show answer & explanation

Correct answer: B

Explanation

Given:

169.89×101.9616.93×33.98+198.11×120.8732.89×35.97=?\frac{169.89 \times 101.96}{16.93 \times 33.98} + \frac{198.11 \times 120.87}{32.89 \times \sqrt{35.97}} = ?

⇒ (170 × 102) / (17 × 34) = (170/17) × (102/34)

= 10 × 3 = 30

⇒ (198 × 121) / (33 × 6) = (198/33) × (121/6)

= 6 × (121/6) = 121

Total = 30 + 121 = 151