Father's age 10 years ago from present was 2 times of the age of his son 8 years ago from present. Son's age after 3 years from present is 32 years. What is the sum of present ages of father and son?
Show answer & explanation
Correct answer: A
Explanation
Let:
Father's current age = F
Son's current age = S
10 years ago: Father's age = 2 × (Son's age 8 years ago)
F − 10 = 2(S − 8)
F − 10 = 2S − 16
F = 2S − 6 ... (1)
3 years from now: Son's age = 32
S + 3 = 32
S = 29
Substitute S = 29 into equation (1):
F = 2(29) − 6 = 58 − 6 = 52
Sum:
F + S = 52 + 29 = 81
Correct Answer: (A) 81 years