SSC CPO 2023 PYQ — Question 142

The correct answer is Option 3 i.e 3.

$\frac{0.04}{0.05}$ of $\frac{(3\frac{1}{3}-2\frac{1}{2})÷\frac{1}{2}of1\frac{1}{4}}{\frac{1}{3}+\frac{1}{5} of \frac{1}{9}}$

⇒ $\frac{0.04}{0.05}$ of $\frac{(\frac{10}{3}-\frac{5}{2})÷\frac{1}{2}of\frac{5}{4}}{\frac{1}{3}+\frac{1}{45}}$

⇒ $\frac{0.04}{0.05}$ of $\frac{(\frac{10}{3}-\frac{5}{2})÷\frac{5}{8}}{\frac{1}{3}+\frac{1}{45}}$

⇒ $\frac{0.04}{0.05}$ of $\frac{(\frac{10}{3}-\frac{5}{2})÷\frac{5}{8}}{\frac{1\times15}{3\times15}+\frac{1}{45}}$

⇒ $\frac{0.04}{0.05}$ of $\frac{(\frac{20}{6}-\frac{15}{6})÷\frac{5}{8}}{\frac{15}{45}+\frac{1}{45}}$

⇒ $\frac{0.04}{0.05}$ of $\frac{(\frac{5}{6})\times\frac{8}{5}}{\frac{16}{45}}$

⇒ $\frac{0.04}{0.05}$ of $\frac{\frac{8}{6}}{\frac{16}{45}}$

⇒ $\frac{0.04}{0.05}$ of ${\frac{8}{6}}\times{\frac{45}{16}}$

⇒ $\frac{0.04}{0.05}$ of ${\frac{45}{12}}$

⇒ $\frac{0.04}{0.05}$ × ${\frac{45}{12}}$ 

⇒ $\frac{4}{5} \times \frac{45}{12}$

⇒ $\frac{9}{3 } = 3$