Elections were held in a society to elect a chairman. There were only two candidates A and B. Candidate B got 25% less votes than candidate A. The number of members who did not cast the vote was same as the number of votes that candidate B got. By how many votes did A win if the society had 20,000 members.
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 2000
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Understanding |
Application |
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Candidate B got 25% less votes than candidate A. The number of members who did not cast the vote was same as the number of votes that candidate B got. |
Suppose A got P votes. So, Number of votes received by B = 0.75P And The number of members who did not cast the vote = 0.75P |
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Society had 20,000 members. |
So, (Total votes – number of members who did not cast the vote) = Votes received by A and B (20000 – 0.75P) = P + 0.75P 2.5P = 20000 P = 8000 Hence, A won by 2000 (= 0.25P) votes. |