Eight years ago, the ratio of ages of A and B was 9 : 10. The ratio of their ages 4 years from now will be 12 : 13. What in the age (in years) of C now, if his age is 6 years more than that of A?
Show answer & explanation
Correct answer: B
Explanation
Correct Answer is option 2 i.e. 50
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Understanding |
Application |
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Eight years ago, ratio of ages of A and B = 9 : 10 Suppose age of A, 8 years ago = 9x Age of B, 8 years ago = 10x
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4 years from now, ages of A and B will be (9x + 12) and (10x + 12) Given that this ratio is 12 : 13 Hence, (9x + 12) : (10x + 12) = 12 : 13 ⇒ 117x + 156 = 120x + 144 ⇒ 3x = 156 – 144 = 12 ⇒ x = 4 Hence, Present age of A = 9 × 4 + 8 = 44 years Present age of C = 44 + 6 = 50 years |