SSC CHSL 2024 PYQ — Question 61

SSC CHSL - 11 July 2024 - Shift 2 • Quantitative Aptitude • Q61

Divide 25 into two parts such that 6 times the larger part added to 4 times the smaller part is equal to 130. Find the larger part.

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 15.

Let the larger part be x and the smaller part be y

According to the question

x + y = 25

⇒ y = 25 - x....(1)

6x + 4y = 130

From equation 1

⇒ 6x + 4(25 - x) = 130

⇒ 6x + 100 - 4x = 130

⇒ 2x = 30

⇒ x = 15

Thus, the largest part is 15