Divide 2310 people in three parties such that half in the first party, one-third in the second party and one-sixth in the third party are all equal.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 420, 630, 1260.
Calculations:
According to the question;
⇒ (1/2)A = (1/3)B = (1/6)C
⇒ 3A = 2B = C
⇒ A : B : C = 2 : 3 : 6
Let the numbers be 2x, 3x and 6x
Total Sum = 2x + 3x + 6x
⇒ 2310 = 11x
⇒ x = 210
The required three numbers are 420, 630 and 1260.