SSC MTS 2024 PYQ — Question 8

SSC MTS - 21/10/2024 - (12:30 PM - 2:30 PM) • Quantitative Aptitude • Q8

Distance between A and B is 1200 km. If they start moving towards each other at same time, they will meet in 24 hrs. If A starts 10 hrs after B, then they will meet after another 20 hrs. What are their respective speeds?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e 30 km/h, 20 km/h.

Let speed of A = x km/h, speed of B = y km/h

When both start together, they meet in 24 hours.

So, (x + y) × 24 = 1200 ⇒ x + y = 50 ...(1)

When A starts 10 hours late, B travels alone for 10 hours, covering 10y km.

Then both travel together for 20 hours, covering 20(x + y) km.

Total distance = 10y + 20(x + y) = 1200 ⇒ 10y + 20x + 20y = 1200 ⇒ 20x + 30y = 1200

⇒ 2x + 3y = 120 ...(2)

From (1), x = 50 - y

⇒ 2(50 - y) + 3y = 120 ⇒ 100 - 2y + 3y = 120 ⇒ 100 + y = 120 ⇒ y = 20

⇒ x = 50 - 20 = 30