SSC CGL 2025 PYQ — Question 73

SSC CGL - 23 Sep 2025 - Shift 1 • Quantitative Aptitude • Q73

Dhanush crosses a road 100 metres wide in 50 seconds. His speed in km/hr is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 7.2 km/h

Speed = Distance / Time

Speed = 100 / 50

Speed = 2 m/s

Convert m/s to km/h: multiply by 18/5

Speed = 2 × 18/5

Speed = 36/5

Speed = 7.2 km/h