cot3θ/cosec2θ + tan3θ/sec2θ + 2 sinθ cosθ = ?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. cosecθsecθ.
Concept used :
Trigonometric functions
Calculations :
⇒ cot3θ/cosec2θ + tan3θ/sec2θ + 2 sinθ cosθ
⇒ (cos3θ/sin3θ) × sin2θ + (sin3θ/cos3θ) × cos2θ + 2 sinθ cosθ
⇒ (cos3θ/sinθ) + (sin3θ/cosθ) + 2sinθcosθ
⇒ (cos4θ + sin4θ)/(sinθ.cosθ) + 2sinθcosθ
⇒ ((cos4θ + sin4θ + 2sin2θ.cos2θ))/(sinθ.cosθ)
⇒ (sin2θ + cos2θ)2/(sinθ.cosθ)
⇒ 1/(sinθ.cosθ)
⇒ cosecθ.secθ