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SSC CHSL 2024 PYQ — Question 71

SSC CHSL - 05 July 2024 - Shift 4 • Quantitative Aptitude • Q71

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[cosec31∘−sec59∘(sin18∘÷cos72∘)×tan26∘cot64∘]+[tan30∘+tan15∘(1−tan30∘tan15∘)]=[\frac{cosec31^{\circ}-sec59^{\circ}}{(sin18^{\circ}÷cos72^{\circ})}×\frac{tan26^{\circ}}{cot64^{\circ}}]+[\frac{tan30^{\circ}+tan15^{\circ}}{(1-tan30^{\circ}tan15{\circ})}]= _______________.

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Correct answer: C

Explanation

The correct answer is option 3 i.e. 1.

[cosec31∘−sec59∘(sin18∘÷cos72∘)×tan26∘cot64∘]+[tan30∘+tan15∘(1−tan30∘tan15∘)][\frac{cosec31^{\circ}-sec59^{\circ}}{(sin18^{\circ}÷cos72^{\circ})}×\frac{tan26^{\circ}}{cot64^{\circ}}]+[\frac{tan30^{\circ}+tan15^{\circ}}{(1-tan30^{\circ}tan15{\circ})}]

=[cosec31∘−cosec31∘(cos72∘÷cos72∘)×tan26∘tan26∘]+tan(30°+15°)=[\frac{cosec31^{\circ}-cosec31^{\circ}}{(cos72^{\circ}÷cos72^{\circ})}×\frac{tan26^{\circ}}{tan26^{\circ}}]+tan(30° + 15°)

=[01×1]+tan45=[\frac{0}{1}×1]+tan 45

=0×1+1=0\times 1+1

= 1