Chords AB and CD of a circle intersect externally at P. If CD = 11.6 cm, PD = 6.4 cm and PB = 7.2 cm, then AB (in cm) is equal to:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 8.8.
PA.PB = PC.PD
(x + 7.2)7.2 = 18 × 6.4
x + 7.2 = 16
x = 8.8