Chord AB of a circle is produced to a point P, and C is a point on the circle such that PC is a tangent to the circle. If PC = 12cm, and BP = 10cm, then the length of AB (in cm) is:
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Correct answer: D
Explanation
The correct answer is Option 4 i.e. 4.4.

Given, PC = 12, BP = 10
As we know,
PB × PA = PC2
⇒ PA × 10 = 122
⇒ PA = (12 × 12)/10
⇒ PA = 14.4
As we know,
⇒ PA = PB + AB
⇒ 14.4 = 10 + AB
⇒ AB = 14.4 -10
⇒ AB = 4.4