Avinash travels 5 km towards east followed by 8 km to his right. He turns left to travel 6 km followed by 5 km towards south. Approximately how far is he from the initial position?
Show answer & explanation
Correct answer: B
Explanation
Let the initial position be the origin .
• Step 1: 5 km towards East
• Step 2: Turns right (South) and travels 8 km
• Step 3: Turns left (East) and travels 6 km
• Step 4: Travels 5 km towards South
Net Displacement:
• Total East distance =
• Total South distance =
Using the Pythagoras theorem, the shortest distance () from the starting point is:
Thus, he is approximately 17 KM away from the initial position.