At 10 × 104 Pa pressure and 300 K temperature, the volume of 0.09 mol CO2 gas is 22.4 × 10−3 m3. What will be the volume of the gas if the pressure is decreased to 2 × 104 Pa?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 112.0 × 10⁻³ m³ .
Given:
P₁ = 10 × 10⁴ Pa
V₁ = 22.4 × 10⁻³ m³
P₂ = 2 × 10⁴ Pa
V₂ = ?
Using Boyle’s Law:
P₁ × V₁ = P₂ × V₂
Substitute the values:
(10 × 10⁴) × (22.4 × 10⁻³) = (2 × 10⁴) × V₂
2240 = 2 × 10⁴ × V₂
Now solve for V₂: V₂ = 2240 / (2 × 10⁴)
V₂ = 112.0 × 10⁻³ m³