SSC CHSL 2021 PYQ — Question 69

SSC CHSL - 13 April 2021 - Shift 1 • Quantitative Aptitude • Q69

Ashok completes a journey in 7 hours. He travels the first half of the journey at the speed of 24 km/h and the second half of it at the speed of 32 km/h. The total distance of the journey is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is Option 4 i.e. 192 km.

Let, Total distance = 2D 

⇒ D/24 + D/32 = 7

⇒ (4D + 3D)/96 = 7

⇒ 7D/96 = 7

⇒ D = 96 km

Total distance = 2D = 2 × 96 = 192 km