The full marks for a paper is 300. The break-up of the marks into theory (X), practical (Y) and project (Z), Which are the three components of evaluation is 6 : 5 : 4. In order to pass one has to score at least 40%, 50% and 50% respectively in X, Y, Z and 60% in aggregate. The marks scored by four students A, B, C and D are shown in the given Bar Graph.
Arrange the students B, C and D according to the ascending order of the aggregate marks scored by them.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. B, D, C
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Application |
Fair calculation |
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The aggregate marks scored by B = (50 × 6/15) + (50 × 5/15) + (30 × 4/15) = 44.66 The aggregate marks scored by C = (70 × 6/15) + (80 × 5/15) + (60 × 4/15) = 70.66 The aggregate marks scored by D = (80 × 6/15) + (70 × 5/15) + (30 × 4/15) = 63.33 Hence, The ascending order = B, D, C |
(50 × 6/15) + (50 × 5/15) + (30 × 4/15) = (300 + 250 + 120)/15 = 670/15 = 44.66 (70 × 6/15) + (80 × 5/15) + (60 × 4/15) = (420 + 400 + 240)/15 = 1060/15 = 70.66 (80 × 6/15) + (70 × 5/15) + (30 × 4/15) = (480 + 350 + 120)/15 = 950/15 = 63.33 |