Aravind runs 5/4 times as fast as Bhanu. In a race, if Aravind gives a 60-meter lead to Bhanu, find the distance from the starting point where both of them will meet.
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 300 m
Given that
Aravind runs 5/4 times as fast as Bhanu
Let the speed of Bhanu be 4x
The speed of Aravind will be 5x
The distance traveled by Aravind is L meter
then the distance traveled by Bhanu is (L - 60) meter
According to the question
Time is constant so the Distance ratio is directly proportional to the speed ratio
⇒ (L - 60)/L = 4X/5X
⇒ 5L - 300 = 4L
⇒ L = 300 meters
Hence, the distance from the starting point where both of them will meet is 300 meters.