Anil started his journey in the morning. Till 10 a.m., he covered 1/2 of his journey, and on the same day till 1 a.m., he covered 4/5 of his journey. At what time did he start his journey?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 5.00 a.m.
Given,
Anil started his journey in the morning. Till 10 a.m., he covered 1/2 of his journey, and on the same day till 1 a.m., he covered 4/5 of his journey
We know that,
Distance = Speed × Time
Let, the total distance be 100D
Till 10 a.m. he covered = 100D × 1/2 = 50D
Till 1 p.m. he covered = 100D × 4/5 = 80D.
Hence, in (1 p.m. 10 a.m.) = 3 hours,
he covered = 80D - 50D = 30D units
Thus, his speed = 30D/3 = 10 units/hr
Time taken to complete remaining journey = (100D - 80D)/10D = 2 hour
Hence, at 3 p.m. he would complete his journey
Total time taken to complete the journey = 100/10 = 10 hours
Thus, he started the journey at = 3 p.m. - 10 hours = 5 a.m.
Hence, he started the journey at 5 a.m.