SSC CHSL 2025 PYQ — Question 73

SSC CHSL - 17 Nov 2025 - Shift 3 • Quantitative Aptitude • Q73

An object is shaped like an ice cream cone, consisting of a hemisphere placed on top of a cone with an identical base radius. The volume of the hemispherical part is 144π cm³, and the height of the conical part is 8 cm. What is the total surface area of the object?

Show answer & explanation

Correct answer: A

Explanation

Given:

Volume of the hemisphere = 144π cubic cm

Height of the cone = 8 cm

Formula:

Volume of the hemisphere = (2/3)πr³

Curved surface area of ​​the cone = πrl

Curved surface area of ​​the hemisphere = 2πr²

Total surface area = πrl + 2πr²

(2/3)πr³ = 144π

r³ = 216

r = 6 cm

Slant height of the cone

l = √(r² + h²)

= √(6² + 8²)

= √(36 + 64)

= √100

= 10 cm

Curved surface area of ​​the cone = πrl

= π × 6 × 10

= 60π

Curved surface area of ​​hemisphere= 2πr²= 2π × 36= 72π

Total surface area = 60π + 72π = 132π cm²