An equilateral triangle of side 6 cm has its corners cut-off to form a regular hexagon. What is the area of this regular hexagon?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e 6
Given that
An equilateral triangle of side 6 cm
now it cutoff from its corner to form a regular hexagon
then the cutoff side will be 2 cm to form a regular hexagon
Formula used
The area of the regular hexagon = 6 (√3/4) side2
Calculation
The area of the regular hexagon = 6 × (√3/4) × 22 = 6√3 cm2