SSC CGL 2020 PYQ — Question 6

SSC CGL Tier II - Quant - 16 Nov 2020 • Quantitative Aptitude • Q6

Amrita travels from her house at 3½ km/h and reaches her school 6 minutes late. The next day she travels at 4½ km/h and reaches her school 10 minutes early. What is the distance between her house and the school?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 4.2 km

Let the usual time to reach at school in t minutes.

Distance = time × speed.

In the first case, Amrita travels from her house at 3½ km/h and reaches her school 6 minutes late

Distance = (t + 6) × 7/2............(1)

In the second case, she travels at 4½ km/h and reaches her school 10 minutes early.

Distance = (t - 10) × 9/2...........(2)

On combining 1 and 2 we get,

7t/2 + 21 = 9t/2 - 45

t = 66 minutes.

Distance = (t + 6) × 7/2.

= 72/60 × 7/2 = 4.2 km.