Alloy A contains metals x and y only in the ratio 5 : 2 and alloy B contains these metals in the ratio 3 : 4 alloy C is prepared by mixing A and B in the ratio 4 : 5. The percentage of x in alloy C is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 55
| x | y | Total | |
| A | 5 units | 2 units |
7 units |
| B | 3 units | 4 units | 7 units |
A and B are mixed in the ratio of 4 : 5
Respective quantities of A and B becomes
| x | y | Total | |
| A | 20 units | 8 units |
28 units |
| B | 15 units | 20 units | 35 units |
Total x in C = 20 + 15 = 35
Total y in C = 8 + 20 = 28.
% of x in C = 35/63 × 100 = 55.55%