Alloy A contains metals x and y only in the ratio 3: 2, while alloy B contains them in the ratio 5: 6 Alloy C is prepared by mixing alloys A and B in the ratio 4: 3. The percentage of x in alloy C is:
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Correct answer: D
Explanation
Given:
Alloy A has x : y = 3 : 2
Alloy B has x : y = 5 : 6
A : B = 4 : 3
Formula:
Percentage = (Quantity of metal ÷ total quantity) × 100
Share of x in A = 3/(3 + 2) = 3/5
Share of x in B = 5/(5 + 6) = 5/11
Share of x in A = 4 × (3/5) = 12/5
Share of x in B = 3 × (5/11) = 15/11
Total x = 12/5 + 15/11
= (132 + 75)/55 = 207/55
Total alloy = 4 + 3 = 7
Share of x = (207/55) ÷ 7 = 207/385
Percentage = (207/385) × 100 = 53.77%
Alloy C contains x = 53.77%