Alloy A contains metals x and y in the ratio 5 : 2 and alloy B contains these metals in the ratio 3 : 4. Alloy C is prepared by mixing A and B in a ratio 4 : 5. The percentage of y in alloy C is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 44
In A = component of x and component of y be 5 units and 2 units = 7 units.
In B = component of x and component of y be 3 units and 4 units = 7 units.
Quantity will be the same in A and B (i.e., if it is not equal then one must make them equal before moving to the next step).
Now to prepare C one mix 4 parts of A and 5 parts of B.
From A, the Components of x and y will be 5 × 4 and 2 × 4 respectively.
From B, the Components of x and y will be 3 × 5 and 4 × 5 respectively.
Componet of x and y in C = 20 + 15 = 35 units.
Components of y in C = 20 + 8 = 28 units.
% of y in C = 28/63 × 100 = 44%.