SSC CHSL 2025 PYQ — Question 59

SSC CHSL - 25 Nov 2025 - Shift 3 • Quantitative Aptitude • Q59

Aditya is twice as good a workman as Bipin and therefore can finish a job in 30 days less than Bipin. How many days are required to complete the job if working together?

Show answer & explanation

Correct answer: B

Explanation

Given:

Aditya is twice as efficient as Bipin.

Aditya completes the work in 30 days less than Bipin.

Let Bipin's time = x days.

Aditya's time = x − 30 days.

Efficiency ratio = 2 : 1.

Time ratio = 1 : 2.

(x − 30) : x = 1 : 2.

2(x − 30) = x.

2x − 60 = x.

x = 60.

Bipin's time = 60 days.

Aditya's time = 30 days.

Together, 1 day's work.

= 1/30 + 1/60.

= 3/60.

= 1/20.

Together, they will complete the work in 20 days.