SarkariPYQ

SSC MTS 2024 PYQ — Question 15

SSC MTS - 09/10/2024 - (9:00 AM - 11:00 AM) • Quantitative Aptitude • Q15

Back to paper

ABCDEF is a regular hexagon, and the length of AD is 12 cm. What is the area (in cm²) of the given hexagon?

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e 54354 \sqrt{3}  .

ABCDEF is a regular hexagon.

Given AD = 12 cm, where A and D are opposite vertices of the hexagon.

In a regular hexagon, the distance between opposite vertices (AD) = 2 × side length.

AD = 12 ⇒ side length = 12 ÷ 2 = 6 cm.

Area = (3√3 / 2) × (side)²

⇒ (3√3 / 2) × 6² = (3√3 / 2) × 36 = 54√3 cm²