ABCD is a trapezium in which AB is parallel to CD and AB = 4(CD). The diagonals of the trapezium intersects at O. What is the ratio of area of triangle DCO to the area of the triangle ABO?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4, i.e. 1 : 16
AB = 4CD
⇒ CD/AB = 1/4
and △DOC ~ △BOA
Hence,
Area of △DOC/ Area of △BOA = CD2/AB2 = 1/16