ABCD is a rectangle. P is a point on the side AB as shown in the figure. If DP = 13, CP = 10, and BP = 6, then what is the value of (AP2 + BC)?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. √105.
DP = 13, CP = 10 and BP = 6
So,
BC = √(102 - 62) = 8 cm
Let AP = a cm
In △ADP
AD2 + AP2 = DP2
⇒ 64 + a2 = 169
⇒ a2 = 105
⇒ a = √105
Value of (AP2 + BC) = (√105)2 + 8
⇒ 105 + 8 = 113