ABCD is a cyclic quadrilateral whose diagonals intersect at P. If ∠DBC = 72º and ∠BAC = 42º , then the measure of ∠BCD (in degrees) is:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 66.
Let's assume ∠BCD = θ
We have given,
∠BAC = 42°
∠DBC = 72°
∠DBC = ∠DAC = 72° (Same segment angles)
∠DAB = 72° + 42° = 114°
So, ∠BCD = 180° - 114° = 66°