ABCD is a cyclic quadrilateral. The tangents to the circle at the points A and C on it, intersect at P. If ∠ABC = 98°, then what is the measure of ∠APC?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 16°
| Understanding | Application |
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According to question:
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Since ∠B and ∠D are the opposite angles of a cyclic quadrilateral So, ∠B + ∠D = 180 ⇒ ∠D = 180 - 98 ⇒ ∠D = 82 So, Let centre is O ∠AOC = 2 × ∠D ∠AOC = 164 |
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Here In quadrilateral AOCP: Sum of all angle = 360 |
Hence, ⇒ ∠AOC + ∠OCP + ∠ACP + ∠CAO = 360 ⇒ 164 + 90 + ∠ACP + 90 = 360 ⇒ ∠ACP = 360 - 344 ⇒ ∠ACP = 16 |
