ABCD is a cyclic quadrilateral. Diagonals BD and AC intersect each other at E. If ∠BED = 138º and ∠ECD = 35º, then what is the mease of ∠BAC?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 103º
∠BEC and ∠CED lie on same straight line
∠BEC = 138°
∠CED = 180° - 138°
⇒ ∠CED = 42°
In ΔCDE, ∠CED = 42° and ∠DCE = 35°
∠CDE = 180° - (42° + 35°)
⇒ ∠CDE = 103°
∠BAC and ∠BDC lie on the same arc BC
Hence ∠BAC = 103°