ABCD is a cyclic quadrilateral and BC is the diameter of the related circle on which A and D also lie. ∠BCA = 19° and ∠CAD = 32º. What is the measure of ∠ACD?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 39⁰
∠BCA + ∠CAD + ∠BAC + ∠ACD = 180º
19º + 32º + 90º + ∠ACD = 180º
∠ACD = 180º - 141º = 39º