ΔABC is similar to ΔDEF. The area of ΔABC is 100 cm2 and the area of ΔDEF is 49 cm2. If the altitude of ΔABC = 5 cm, then the corresponding altitude of ΔDEF is:
Show answer & explanation
Correct answer: C
Explanation
Correct Answer is option 4 i.e. 3.5 cm
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Concept |
Understanding |
Application |
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If 2 triangles A and B are similar: Area of triangle A/Area of triangle B = (altitude of A)2/(altitude of B)2 |
ΔABC is similar to ΔDEF Area of ∆ABC = 100 cm2 Area of ∆DEF = 49 cm2 ΔABC's altitude = 5 cm Suppose altitude of DEF = p |
Hence, 100/49 = 52/p2 ⇒ p = 5 × 7/10 ⇒ p = 3.5 cm |