ΔABC is similar to ΔDEF. If area of ΔABC is 9 sq.cm. and area of ΔDEF is 16 sq.cm. and BC = 2.1 cm, then the length of EF will be:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 2.8 cm
If triangle are similar then:
Area of ΔABC : Area of ΔDEF = BC2 : EF2
⇒ 9 : 16 = BC2 : EF2
⇒ 3 : 4 = BC : EF
⇒ EF = 4/3 × 2.1 = 2.8 cm