∆ABC is inscribed in a circle with Centre O. If AB = 21 cm, BC = 20 cm, and AC = 29 cm, then what is the length of the circumradius of the triangle?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 14.5 cm.
AB = 21 cm, BC = 20 cm and AC = 29 cm
We know that (21, 20, 29) is a triplet.
△ABC is a right-angle triangle where ∠B = 90°
The circumradius of a right triangle is half the length of its hypotenuse.
Circumradius = 29/2 = 14.5 cm
Therefore, the length of the circumradius of the triangle is 14.5 cm.