SSC CGL 2016 PYQ — Question 21

SSC CGL Tier II Quant - 30/11/2016 • Quantitative Aptitude • Q21

ABC is a triangle, PQ is line segment intersecting AB at P and AC at Q and PQ II BC. AP : BP = 3 : 5 and length of PQ is 18 cm. The length of BC is:

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 48 cm

AP/BP = 3/5 and PQ = 18 cm

AP/AB = 3/8

Since PQ II BC, triangles APQ and ABC are similar triangles.

So,

AP/AB = PQ/BC

⇒ 3/8 = 18/BC

⇒ BC = 48 cm