SSC CHSL 2024 PYQ — Question 51

The correct answer is option 2 i.e. 8.5 cm.

When ∆ABC and ∆PQR are similar, then

$({Area of ABC \over Area of PQR})= ({AB \over PQ})^2 = ({BC \over QR})^2 = ({AC \over PR})^2$

According to the given question,

Let the size of AC be x cm.

(AC/PR)² = 289/576

⇒ x/12 = 17/24

⇒ x = 8.5 cm