AB is a chord of a circle in minor segment with centre O. C is a point on the minor arc of the circle between the points A and B. The tangents to the circle at A and B meet at the point P. If ∠ACB = 102º, then what is the measure of ∠APB?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 24º

ACB + ADC = 180 (Cyclic quadrilateral)
ADC = 180 - 102 = 78°
AOB = 2 × ADC ( Angle subtended by the arc at the centre is twice of the angle subtended by the same arc at the circumference)
AOB = 2 × 78 = 156°.
AOB + APB = 180°
APB = 180 - 156 = 24°.