AB is a chord in the minor segment of a circle with centre O. C is a point on the minor arc (between A and B). The tangents to the circle at A and B meet at a point P. If ACB = 108º, then APB is equal to:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 36º.

ACB = 108°
ACB + ADB = 180°
ADB = 180 - 108 = 72°.
AOB = 2 × ADB
AOB = 2 × 72 = 144°.
AOB + APB = 180
APB = 180 - 144 = 36°.