SSC CGL 2019 PYQ — Question 13

SSC CGL Tier II - Quant 13th Sep. 19 • Quantitative Aptitude • Q13

ab(a - b) + bc(b - c) + ca(c - a) is equal to:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. (b - a)(b - c)(c - a).

Trick: Asumes values of a, b, c

Let us assume a = 1, b = 2, c = 3

= 2(-1) + 6(-1) + 3(2)

= - 2

Now check the value of options