SSC CHSL 2021 PYQ — Question 72

SSC CHSL - 12 April 2021 - Shift 3 • Quantitative Aptitude • Q72

A truck covers a distance of 480 km at a certain speed. If the speed is decreased by 8km/h, it would have taken 2 hours more to cover the same distance, 50% of its original speed (in km) is:

Show answer & explanation

Correct answer: C

Explanation

The correct answer in option 3 i.e. 24

Let the speed of the truck be = x km/h

Hence;

480 km/(x - 8) - 480 km/x = 2 hours

⇒ 1/(x - 8) - 1/x = 2/480 

⇒ x - x + 8/(x - 8)x = 1/240

⇒ 8 × 240 = x2 - 8x 

⇒ x2 - 8x - 1920 =0 

⇒ x2 + 40x - 48x - 1920 = 0

⇒ x(x + 40) - 48(x + 40) = 0

⇒  x = 48 since speed cant be a negative value

50% of the original speed = 48 × 1/2 = 24 km/h