A triangle ABC is made on a circle, where AB is the diameter of the circle. If BC is equal to the radius of the circle and ∠ABC = x ∠BAC, then x is :
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 2.

In △ABC
⇒ AB2 = AC2 + BC2
⇒ (2r)2 = AC2 + r2
⇒ 4r2 = AC2 + r2
⇒ AC2 = 3r2
⇒ AC =
Now,
⇒ sin∠BAC = BC/AB = r/2r = 1/2
⇒ sin∠BAC = sin 30°
⇒ ∠BAC = 30°
Since ∠ACB = 90°,
⇒ ∠ACB = 90° - 30° = 60°
So,
⇒ ∠ABC = x × ∠BAC
⇒ 60° = x × 30°
⇒ x = 60°/30°
⇒ x = 2