SSC MTS 2022 PYQ — Question 65

The correct answer is Option 4 i.e. 43.2 km.

Time = 2 h

Speed = 6 m/s

Distance = Speed × time

Speed(in km/h) = Speed(in m/s) $\times {18\over 5}$

Speed of train (in km/h) = $6 \times {18\over 5}$=$108 \over 5$ km/h

Now, Distance travelled = Speed × time = $108 \over 5$ × 2 = 43.2 km

Hence the distance covered by the train is 43.2 km.