A train travelling at the speed of 65 km/h leaves Bombay at 10 : 00 a.m., and another train travelling at the speed of 76 km/h starts at 12 : 00 p.m. in the same direction. At what distance (in km) from Bombay will they be together?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 898.18 km.
A train travelling at a speed of 65 km/h leaves Bombay at 10:00 A.M.
Another train travelling at 76 km/h starts at 12:00 P.M in same direction
Relative speed of trains travelling in the same direction = Difference between the speeds of two trains
Time taken =
The relative speed of trains when they travel in the same direction = 76 - 65 = 11 km/h
Total time taken to be together = 12 p.m. - 10 a.m. = 2 hours
The distance from Bombay covered by the first train till 12 p.m. = 65 × 2 = 130 km
The time taken to overtake the first train by another train = hours
Distance covered by second train = 76 × hours = 898.18 km