SSC MTS 2024 PYQ — Question 3

SSC MTS - 01/10/2024 - (12:30 PM - 2:30 PM) • Quantitative Aptitude • Q3

A train travelling at a speed of 60 km/h leaves station A at 7:00 a.m., and another train travelling at a speed of 84 km/h starts from station A at 9:30 a.m. in the same direction on a parallel track. At what distance (in km) from station A and after how many hours of travel of the second train will they be together? Express your answer in the same order.

Show answer & explanation

Correct answer: C

Explanation

The correct answer is Option 3 i.e. 525, 6.25.

Let the trains meet after t hours of travel of the second train.

Distance covered by first train in t + 2.5 hours: 60(t + 2.5)

Distance covered by second train in t hours: 84t

⇒ 60(t + 2.5) = 84t

⇒ 60t + 150 = 84t

⇒ 24t = 150

⇒ t = 6.25

Distance from station A = 84 × 6.25 = 525 km